STPS15L45CB STMicroelectronics

STPS15L45C Datasheet 2 x 7.5 A - 45 V low drop power Schottky rectifier Features A1 Very small conduction losses K Negligible switching losses A2 Extremely fast switching K K Low forward voltage drop Low capacitance Avalanche capability specified A2 ECOPACK2 compliant component A2 A1 A1 DPAK Applications SMPS Freewheeling diodes Switching diodes Description Dual center tab Schottky rectifier suited for SMPS and high frequency DC to DC converters. Packaged in DPAK, the STPS15L45C is intended for use in low voltage, high frequency inverters, freewheeling and polarity protection applications. Product status link STPS15L45C Product summary Symbol Value I F(AV) 2 x 7.5 A V 45 V RRM T 150 C j(max.) V 0.40 V F(typ.) DS2653 - Rev 6 - April 2020 www.st.com For further information contact your local STMicroelectronics sales office.STPS15L45C Characteristics 1 Characteristics Table 1. Absolute ratings (limiting values, per diode, at 25 C unless otherwise specified) Symbol Parameter Value Unit V Repetitive peak reverse voltage 45 V RRM I Forward rms current 10 A F(RMS) Per diode 7.5 I Average forward current T = 140 C, = 0.5 square wave A F(AV) c Per device 15 I t = 10 ms sinusoidal Surge non repetitive forward current 75 A FSM p P t = 10 s, T = 125 C Repetitive peak avalanche power 265 W ARM p j T Storage temperature range -65 to +175 C stg (1) T Maximum operating junction temperature 150 C j 1. (dP /dT ) < (1/R ) condition to avoid thermal runaway for a diode on its own heatsink. tot j th(j-a) Table 2. Thermal resistance parameters Symbol Parameter Max. value Unit Per diode 4 R Junction to case th(j-c) Total 2.4 C/W R Coupling 0.7 th(c) When the diodes 1 and 2 are used simultaneously : T (diode 1) = P(diode1) x R (per diode) + P(diode 2) x R j th(j-c) th(c) For more information, please refer to the following application note : AN5088 : Rectifiers thermal management, handling and mounting recommendations Table 3. Static electrical characteristics (per diode) Symbol Parameter Test conditions Min. Typ. Max. Unit T = 25 C - 500 A j (1) I Reverse leakage current V = V R R RRM T = 125 C - 60 120 mA j T = 25 C - 0.52 j I = 7.5 A F T = 125 C - 0.40 0.46 j T = 25 C - 0.60 j (2) V I = 12 A Forward voltage drop V F F T = 125 C - 0.49 0.57 j T = 25 C - 0.64 j I = 15 A F T = 125 C - 0.53 0.63 j 1. Pulse test: t = 5 ms, < 2% p 2. Pulse test: t = 380 s, < 2% p To evaluate the conduction losses, use the following equation: DS2653 - Rev 6 page 2/10