STTH8R02DDJFY-TR STMicroelectronics

STTH8R02D-Y Automotive ultrafast rectifier Datasheet - production data A1 K1 Description A2 K2 The STTH8R02D-Y is especially suited for switching mode base drive and transistor circuits. The device is also intended for use as a free wheeling diode in power supplies and other power switching applications in automotive functions. Table 1: Device summary Symbol Value IF(AV) 2 x 4 A VRRM 200 V Tj (max.) 175 C V (typ.) 0.71 V F trr (typ.) 16 ns Features AEC-Q101 qualified Very low conduction losses Negligible switching losses Low forward and reverse recovery times High junction temperature ECOPACK 2 compliant component PPAP capable Dual Island package Wettable flanks for automatic visual inspection July 2017 DocID029557 Rev 2 1/10 www.st.com This is information on a product in full production. Characteristics STTH8R02D-Y 1 Characteristics Table 2: Absolute ratings (limiting values per diode at 25 C, unless otherwise specified) Symbol Parameter Value Unit Repetitive peak reverse V T = -40 C to +175 C 200 V RRM j voltage I Average forward current T = 150 C , = 0.5 square pulse 4 A F(AV) c IF(RMS) Forward rms current 10 A Surge non repetitive forward IFSM tp = 8.3 ms sinusoidal 75 A current Tstg Storage temperature range -65 to +175 C (1) T Maximum operating junction temperature -40 to +175 C j Notes: (1) (dP /dT ) < (1/R ) condition to avoid thermal runaway for a diode on its own heatsink. tot j th(j-a) Table 3: Thermal resistance parameters Symbol Parameter Maximum Unit Per diode 5 Rth(j-c) Junction to case Total 3 C/W Coupling 1 Table 4: Static electrical characteristics (per diode) Symbol Parameter Test conditions Min. Typ. Max. Unit T = 25 C - 3 j (1) IR Reverse leakage current VR = VRRM A Tj = 125 C - 2 20 T = 25 C - 0.90 1.05 j Tj = 125 C IF = 3 A - 0.87 T = 150 C - 0.71 0.83 j Tj = 25 C - 0.94 1.10 (2) V Forward voltage drop T = 125 C I = 4 A - 0.92 V F j F Tj = 150 C - 0.76 0.88 T = 25 C - 1.05 1.22 j Tj = 125 C IF = 8 A - 1.07 T = 150 C - 0.89 1.04 j Notes: (1) Pulse test: tp = 5 ms, < 2% (2) Pulse test: tp = 380 s, < 2% To evaluate the conduction losses use the following equation: 2 P = 0.72 x I + 0.040 x I F(AV) F (RMS) 2/10 DocID029557 Rev 2