STPS16H100CG-TR STMicroelectronics

STPS16H100C High voltage power Schottky rectifier Datasheet - production data Description A1 K Dual center tap Schottky rectifier designed for A2 high frequency miniature switch mode power supplies such as adaptors and on-board DC-DC K K converters. Table 1: Device summary Symbol Value A2 IF(AV) 2x 8 A A2 A1 A1 V 100 V RRM 2 Tj (max) 175 C D PAK V (typ) 0.59 V F Features Negligible switching losses High junction temperature capability Low leakage current Good trade off between leakage current and forward voltage drop Avalanche capability specified ECOPACK 2 compliant component for DPAK on demand April 2015 DocID8734 Rev 3 1/10 www.st.com This is information on a product in full production. Characteristics STPS16H100C 1 Characteristics Table 2: Absolute ratings (limiting values, per diode, at 25 C, unless otherwise specified) Symbol Parameter Value Unit VRRM Repetitive peak reverse voltage 100 V I Forward rms current 30 A F(RMS) T = 165 C Per diode 8 C Average forward current = 0.5, IF(AV) A square wave T = 160 C Per device 16 C Surge non repetitive forward IFSM tp = 10 ms sinusoidal 200 A current PARM Repetitive peak avalanche power tp = 10 s, Tj= 125 C 625 W T Storage temperature range -65 to + 175 C stg (1) Tj Maximum operating junction temperature + 175 C Notes: (1) (dP /dT ) < (1/R ) condition to avoid thermal runaway for a diode on its own heatsink. tot j th(j-a) Table 3: Thermal parameter Symbol Parameter Value Unit Per diode 1.6 Rth(j-c) Junction to case C/W Total 1.1 R Coupling 0.6 C/W th(c) When the diodes 1 and 2 are used simultaneously : Tj(diode 1) = P(diode1) x R (Per diode) + P(diode 2) x R th(j-c) th(c) Table 4: Static electrical characteristics (per diode) Symbol Parameter Test conditions Min. Typ. Max. Unit Tj = 25 C - 3.6 A (1) I Reverse leakage current V = V R R RRM T = 125 C - 1.6 5 mA j Tj = 25 C - 0.77 I = 8 A F T = 125 C - 0.59 0.64 j (2) VF Forward voltage drop V Tj = 25 C - 0.88 I = 16 A F T = 125 C - 0.67 0.73 j Notes: (1) Pulse test: t = 5 ms, < 2% p (2) Pulse test: tp = 380 s, < 2% To evaluate the conduction losses use the following equation: 2 P = 0.55 x IF(AV) + 0.011 IF (RMS) 2/10 DocID8734 Rev 3