STPS1L20MF Low drop power Schottky rectifier in flat package Features A Very low profile package: 0.85 mm Backward compatible with standard STmite footprint K Very small conduction losses Negligible switching losses STmite flat (DO222-AA) Extremely fast switching Low forward voltage drop for higher efficiency Table 1. Device summary and extended battery life Symbol Value Low thermal resistance Avalanche capability specified I 1 A F(AV) V 20 V RRM Description T (max) 150 C j Single Schottky rectifier suited for switch mode V (max) 0.37 V F power supplies and high frequency dc to dc converters. Packaged in STmite flat, this device is intended for use in low voltage, high frequency inverters, free wheeling and polarity protection applications. Due to the very small size of the package this device fits battery powered equipment (cellular, notebook, PDAs, printers) as well as chargers and PCMCIA cards. July 2011 Doc ID 12640 Rev 2 1/7 www.st.com 7Characteristics STPS1L20MF 1 Characteristics Table 2. Absolute ratings (limiting values) Symbol Parameter Value Unit V Repetitive peak reverse voltage 20 V RRM I Forward current rms 2 A F(RMS) I Average forward current T = 140 C = 0.5 1 A F(AV) c I Surge non repetitive forward current t = 10 ms sinusoidal 50 A FSM p P Repetitive peak avalanche power t = 1 s T = 25 C 1400 W ARM p j T Storage temperature range - 65 to + 150 C stg (1) T Maximum operating junction temperature 150 C j dV/dt Critical rate of rise of reverse voltage (rated V , T = 25 C) 10000 V/s R j dPtot 1 --------------- -------------------------- 1. < condition to avoid thermal runaway for a diode on its own heatsink dTj Rth()j a Table 3. Thermal resistance Symbol Parameter Value Unit R Junction to case 20 C/W th(j-c) (1) R Junction to ambient 250 C/W th(j-a) 1. Mounted with minimum recommended pad size, PC board FR4 Table 4. Static electrical characteristics Symbol Parameter Tests conditions Min. Typ. Max. Unit T = 25 C 0.015 0.075 j V = V R RRM T = 85 C 0.90 4.50 j T = 25 C 0.005 0.035 j (1) I Reverse leakage current V = 10 V mA R R T = 85 C 0.45 2.50 j T = 25 C 0.003 0.025 j V = 5 V R T = 85 C 0.30 1.60 j T = 25 C 0.38 0.43 j I = 1 A F T = 85 C 0.32 0.37 j T = 25 C 0.42 0.47 j I = 2 A F T = 85 C 0.37 0.42 j (1) V Forward voltage drop V F T = 25 C 0.46 0.53 j I = 3 A F T = 85 C 0.42 0.49 j T = 25 C 0.50 0.60 j I = 4 A F T = 85 C 0.46 0.56 j 1. Pulse test: = 380 s, < 2% To evaluate the conduction losses use the following equation: 2 P = 0.32 x I + 0.05 I F(AV) F (RMS) 2/7 Doc ID 12640 Rev 2