STPS20SM100S Datasheet 100 V power Schottky rectifier Features A(1) K(2) High current capability A(3) Avalanche rated K K Low forward voltage drop High frequency operation A ECOPACK 2 compliant A K A A K TO-220AB IPAK Applications Switching diode SMPS DC/DC converter LED lighting Desktop power supply Description This single Schottky rectifier is suited for high frequency switch mode power supply. Packaged in TO-220AB and IPAK, the STPS20SM100S is intended to be used in notebook, game station and desktop adaptors, providing in these applications a good efficiency at both low and high load. Product status link STPS20SM100S Product summary I 20 A F(AV) V 100 V RRM T (max.) 150 C j V (typ.) 0.63 V F DS6172 - Rev 4 - October 2018 www.st.com For further information contact your local STMicroelectronics sales office.STPS20SM100S Characteristics 1 Characteristics Table 1. Absolute ratings (limiting values, with terminals 1 and 3 short circuited, at 25 C, unless otherwise specified) Symbol Parameter Value Unit V Repetitive peak reverse voltage 100 V RRM I Forward rms current 30 A F(RMS) I Average forward current = 0.5, square wave T = 125 C 20 A F(AV) C I Surge non repetitive forward current t = 10 ms sinusoidal 350 A FSM p P Repetitive peak avalanche power t = 10 s, T = 125 C 1080 W ARM p j T Storage temperature range -65 to +150 C stg (1) T Maximum operating junction temperature 150 C j 1. (dP /dT ) < (1/R ) condition to avoid thermal runaway for a diode on its own heatsink. tot j th(j-a) Table 2. Thermal resistance parameter Symbol Parameter Max. value Unit R Junction to case 1.3 C/W th(j-c) For more information, please refer to the following application note: AN5088: Rectifiers thermal management, handling and mounting recommendations Table 3. Static electrical characteristics (with terminals 1 and 3 short circuited) Symbol Parameter Test conditions Min. Typ. Max. Unit T = 25 C - 10 30 A j V = V R RRM T = 125 C - 10 30 mA j (1) I Reverse leakage current R T = 25 C - 5 A j V = 70 V R T = 125 C - 5 mA j T = 25 C - 565 j I = 5 A F T = 125 C - 480 j T = 25 C - 685 j (2) V Forward voltage drop I = 10 A mV F F T = 125 C - 560 620 j T = 25 C - 800 900 j I = 20 A F T = 125 C - 630 700 j 1. Pulse test: t = 5 ms, < 2% p 2. Pulse test: t = 380 s, < 2% p To evaluate the conduction losses, use the following equation: 2 P = 0.6 x I + 0.005 x I F(AV) F (RMS) For more information, please refer to the following application notes related to the power losses: AN604: Calculation of conduction losses in a power rectifier DS6172 - Rev 4 page 2/10