STPS1150-Y Datasheet Automotive power Schottky rectifier Features K A AEC-Q101 qualified Negligible switching losses Low forward voltage drop for higher efficiency and extended battery life A Low thermal resistance K Surface mount miniature package SMA Avalanche capability specified ECOPACK 2 compliant component PPAP capable Description This 150 V power Schottky rectifier is ideal for switch mode power supplies on up to 24 V rails and high frequency converters. Packaged in SMA, the STPS1150-Y is intended for use in ECU (Engine Control Unit) and fly-back converters in automotive applications where low drop forward voltage is required to reduce power dissipation. Product status STPS1150-Y Product summary Symbol Values I 1 A F(AV) V 150 V RRM T 175 C j (max) V 0.67 V F(max) DS7258 - Rev 3 - April 2018 www.st.com For further information contact your local STMicroelectronics sales office.STPS1150-Y Characteristics 1 Characteristics Table 1. Absolute ratings (limiting values, at 25 C unless otherwise specified) Symbol Parameter Value Unit V Repetitive peak reverse voltage, T = -40 C to +175 C 150 V RRM j I Forward rms current 15 A F(RMS) I Average forward current T = 150 C, = 0.5 square wave 1 A F(AV) L I Surge non repetitive forward current t = 10 ms sinusoidal 50 A FSM p P Repetitive peak avalanche power t = 10 s, T = 125 C 108 W ARM p j T Storage temperature range -65 to +175 C stg (1) T Operating junction temperature range -40 to +175 C j 1. (dP /dT ) < (1/R ) condition to avoid thermal runaway for a diode on its own heatsink. tot j th(j-a) Table 2. Thermal resistance parameters Symbol Parameter Max. value Unit R Junction to lead 30 C/W th(j-l) Table 3. Static electrical characteristics Symbol Parameter Test conditions Min. Typ. Max. Unit T = 25 C - 0.2 1.0 A j (1) I Reverse leakage current V = V R R RRM T = 125 C - 0.2 1.0 mA j T = 25 C - 0.78 0.82 j I = 1 A F T = 125 C - 0.62 0.67 j (2) V Forward voltage drop V F T = 25 C - 0.85 0.89 j I = 2 A F T = 125 C - 0.69 0.75 j 1. t = 5 ms, < 2% p 2. t = 380 s, < 2% p To evaluate the conduction losses, use the following equation: 2 P = 0.59 x I + 0.08 x I F(AV) F (RMS) DS7258 - Rev 3 page 2/9