STPS120L15 Datasheet 15 V power Schottky rectifier A1 K1 Features Very low forward voltage drop A2 K2 Avalanche capability Insulated package ISOTOP: A1 Insulated voltage: 2500 V sine RMS K1 ECOPACK 2 compliant A2 Applications K2 OR-ing diode TM ISOTOP Server Telecom power Heavy duty application Description Dual Schottky rectifier suited for SMPS and DC to DC power converters. TM Packaged in ISOTOP , the STPS120L15 is especially intended for use as an OR- ing diode in fault tolerant power supply equipments. TM Note: ISOTOP is an ST trademark. Product status link STPS120L15 Product summary Symbol Value I 2 x 60 A F(AV) V 15 V RRM T (max.) 125 C j V (typ.) 0.27 V F DS1246 - Rev 7 - September 2018 www.st.com For further information contact your local STMicroelectronics sales office.STPS120L15 Characteristics 1 Characteristics Table 1. Absolute ratings (limiting values at 25 C unless otherwise specified, per diode) Symbol Parameter Value Unit V Repetitive peak reverse voltage 15 V RRM I Forward rms current 160 A F(RMS) I Average forward current , = 1 square wave T = 115 C 60 A F(AV) c I Surge non repetitive forward current t = 10 ms sinusoidal 1200 A FSM p P Repetitive peak avalanche power t = 10 s, T = 125 C 5186 W ARM p j T Storage temperature range -65 to +150 C stg (1) T 125 C j Maximum operating junction temperature 1. (dP /dT ) < (1/R ) condition to avoid thermal runaway for a diode on its own heatsink. tot j th(j-a) Table 2. Thermal resistance parameters Symbol Parameter Max. value Unit Per diode 0.45 R Junction to case th(j-c) Total 0.28 C/W R Coupling 0.1 th(c) When the diodes 1 and 2 are used simultaneously : T (diode 1) = P(diode1) x R (Per diode) + P(diode 2) x R j th(j-c) th(c) For more information, please refer to the following application note: AN5088 : Rectifiers thermal management, handling and mounting recommendations Table 3. Static electrical characteristics (per diode) Symbol Parameter Test conditions Min. Typ. Max. Unit T = 100 C V = 5 V - 450 j R mA (1) T = 25 C I Reverse leakage current - 22 R j V = 12 V R T = 100 C - 0.7 2.2 A j T = 25 C - 0.43 j (1) V Forward voltage drop I = 60 A V F F T = 125 C - 0.27 0.31 j 1. Pulse test: t = 380 s, < 2% p To evaluate the conduction losses, use the following equation: 2 P = 0.18 x I + 0.0022 x I F(AV) F (RMS) For more information, please refer to the following application notes related to the power losses : AN604: Calculation of conduction losses in a power rectifier AN4021: Calculation of reverse losses on a power diode DS1246 - Rev 7 page 2/9