STPS140 Datasheet 40 V, 1 A power Schottky rectifier Features Very small conduction losses Negligible switching losses Low forward voltage drop Surface mount miniature packages Avalanche rated ECOPACK2 compliant Applications Reverse polarity protection Set-top box power supply TV power supply Battery charger Description Single chip Schottky rectifiers suited to switched mode power supplies and high frequency DC to DC converters. Packaged in SMA, SMA Flat Notch and SMB, the STPS140 is ideal for use in surface mounting and used in low voltage, high frequency inverters, free-wheeling and polarity protection applications. Product status STPS140 Product summary Symbol Value I F(AV) 1 A V 40 V RRM T 150 C j(max.) V 0.43 V F(typ.) DS1044 - Rev 9 - September 2019 www.st.com For further information contact your local STMicroelectronics sales office.STPS140 Characteristics 1 Characteristics Table 1. Absolute ratings (limiting values at 25 C, unless otherwise specified) Symbol Parameter Value Unit V Repetitive peak reverse voltage 40 V RRM I Forward rms current 7 A F(RMS) T = 130 C SMA L I T = 135 C Average forward current = 0.5, square wave SMA Flat Notch 1 A F(AV) L SMB T = 135 C L I Surge non repetitive forward current t = 10 ms sinusoidal 60 A FSM p P Repetitive peak avalanche power t = 10 s, T = 125 C 65 W ARM p j T Storage temperature range -65 to +150 C stg (1) T Operating junction temperature +150 C j 1. (dP /dT ) < (1/R ) condition to avoid thermal runaway for a diode on its own heatsink. tot j th(j-a) Table 2. Thermal resistance parameter Symbol Parameter Max. value Unit SMA 30 R Junction to lead SMA Flat Notch 20 C/W th(j-l) SMB 25 For more information, please refer to the following application note : AN5088 : Rectifiers thermal management, handling and mounting recommendations Table 3. Static electrical characteristics Symbol Parameter Test conditions Min. Typ. Max. Unit T = 25 C - 12 A j (1) V = V I Reverse leakage current R R RRM T = 100 C - 0.25 2 mA j T = 25 C - 0.55 j I = 1 A F T = 125 C - 0.43 j (2) V Forward voltage drop V F T = 25 C - 0.65 j I = 2 A F T = 125 C - 0.53 0.60 j 1. Pulse test: t = 5 ms, < 2% p 2. Pulse test: t = 380 s, < 2% p To evaluate the conduction losses, use the following equation: 2 P = 0.40 x I + 0.10 x I F(AV) F (RMS) For more information, please refer to the following application notes related to the power losses : AN604: Calculation of conduction losses in a power rectifier AN4021: Calculation of reverse losses on a power diode DS1044 - Rev 9 page 2/13