STPS2150 Datasheet 150 V, 2 A power Schottky rectifier Features Negligible switching losses Low forward voltage drop for higher efficiency and extended battery life Low thermal resistance Surface mount miniature package Avalanche capability specified ECOPACK2 compliant Applications Switching diode SMPS DC/DC converter Telecom power Description This 150 V power Schottky rectifier is ideal for switch mode power supplies on up to 24 V rails and high frequency converters. Packaged in SMA, SMA Flat Notch and axial, the STPS2150 is optimized for use in consumer and computer applications where low drop forward voltage is required to reduce power dissipation. Product status link STPS2150 Product status link Symbol Values I F(AV) 2 A V 150 V RRM T 175 C j (max.) V 0.62 V F(typ.) DS3282 - Rev 8 - September 2019 www.st.com For further information contact your local STMicroelectronics sales office.STPS2150 Characteristics 1 Characteristics Table 1. Absolute ratings (limiting values, at 25 C, unless otherwise specified) Symbol Parameter Value Unit V Repetitive peak reverse voltage 150 V RRM I Forward rms current 30 A F(RMS) T = 145 C SMA L Average forward current = I T = 145 C SMA Flat Notch 2 A F(AV) L 0.5, square wave DO-15 T = 130 C L SMA 75 Surge non repetitive forward I t = 10 ms sinusoidal FSM SMA Flat Notch p 70 A current DO-15 150 Repetitive peak avalanche P t = 10 s, T = 125 C 170 W ARM p j power T Storage temperature range -65 to + 175 C stg (1) T + 175 C j Maximum operating junction temperature 1. (dP /dT ) < (1/R ) condition to avoid thermal runaway for a diode on its own heatsink. tot j th(j-a) Table 2. Thermal resistance parameter Symbol Parameter Value Unit SMA 20 Junction to lead R SMA Flat Notch 20 C/W th(j-L) Junction to lead Lead length = 10 mm DO-15 30 For more information, please refer to the following application note : AN5088 : Rectifiers thermal management, handling and mounting recommendations Table 3. Static electrical characteristics Symbol Parameter Test conditions Min. Typ. Max. Unit T = 25 C - 0.5 1.5 A j Reverse leakage (1) I V = V R R RRM current T = 125 C - 0.5 1.5 mA j T = 25 C - 0.78 0.82 j I = 2 A F T = 125 C - 0.62 0.67 j Forward voltage (2) V V F drop T = 25 C j - 0.86 0.89 I = 4 A F T = 125 C - 0.70 0.75 j 1. Pulse test: t = 5 ms, < 2% p 2. Pulse test: t = 380 s, < 2% p 2 To evaluate the conduction losses use the following equation: P = 0.59 x I + 0.04 I F(AV) F (RMS) DS3282 - Rev 8 page 2/13