STTH1002CSF Datasheet 200 V, dual 5 A ultrafast rectifier Features 175 C maximum operation junction temperature High surge current capability ECOPACK2 compliant component Application DC/DC converters Freewheeling diodes LED Lighting Description The STTH1002CSF has been developed for applications requiring an optimized VF and reverse recovery characteristics. These characteristics make it ideal for use in secondary rectification functions, such as DC/DC converters or lighting applications. Product status link STTH1002CSF Product summary Symbol Value I F(AV) 2 X 5 A V 200 V RRM t (max) 27 ns rr T (max.) 175 C j V (typ.) 0.79 V F DS13535 - Rev 1 - October 2020 www.st.com For further information contact your local STMicroelectronics sales office.STTH1002CSF Characteristics 1 Characteristics Table 1. Absolute ratings (limiting values at 25 C, unless otherwise specified, per diode) Symbol Parameter Value Unit V Repetitive peak reverse voltage 200 V RRM T = 160 C Per diode 5 c I Average forward current, = 0.5 A F(AV) T = 160 C Per device 10 c I t = 10 ms sinusoidal Surge non repetitive forward current 85 A FSM p T Storage temperature range -65 to +175 C stg T Maximum operating junction temperature range +175 C j Table 2. Thermal resistance parameters Symbol Parameter Typ. Unit Per diode 2.45 R Junction to case C/W th(j-c) Per device 1.66 Rth(c) Coupling 0.87 C/W For more information, please refer to the following application note: AN5088: Rectifiers thermal management, handling and mounting recommendations When the diodes 1 and 2 are used simultaneously: T = P x R (per diode) + P x R j (diode1) (diode1) th(j-c) (diode2) th(c) Table 3. Static electrical characteristics (per diode) Symbol Parameter Test conditions Min. Typ. Max. Unit T = 25 C - 4 j (1) I V = V Reverse leakage current A R R RRM T = 125 C - 4 40 j T = 25 C - 0.91 1.05 j I = 5 A F T = 125 C - 0.79 0.91 j (2) V Forward voltage drop V F T = 25 C - 1.02 1.17 j I = 10 A F T = 125 C - 0.90 1.04 j 1. Pulse test: t = 5 ms, < 2% p 2. Pulse test: t = 380 s, < 2% p To evaluate the conduction losses, use the following equation: 2 P = 0.78 x I + 0.026 x I F(AV) F (RMS) For more information, please refer to the following application notes related to the power losses: AN604: Calculation of conduction losses in a power rectifier AN4021: Calculation of reverse losses in a power diode DS13535 - Rev 1 page 2/10