STTH16L06CG-TR STMicroelectronics

STTH16L06C Turbo 2 ultrafast high voltage rectifier Features A1 Ultrafast switching K A2 Low reverse recovery current Reduces switching and conduction losses Low thermal resistance A2 A2 Description K K A1 A1 The STTH16L06, which is using ST Turbo 2 600 V TO-220AB TO-220FPAB technology, is specially suited for use in switching STTH16L06CT STTH16L06CFP power supplies, and industrial applications, as rectification and discontinuous mode PFC boost K diode. A2 A1 2 D PAK STTH16L06CG Table 1. Device summary I Up to 2 x 10 A F(AV) V 600 V RRM T 175 C j V (typ) 1.05 V F t (max) 35 ns rr April 2011 Doc ID 10760 Rev 2 1/10 www.st.com 10Characteristics STTH16L06C 1 Characteristics Table 2. Absolute ratings (limiting values) Symbol Parameter Value Unit V Repetitive peak reverse voltage 600 V RRM I Forward rms current 30 A F(RMS) T = 140 C Per diode 8 c T = 135 C Per device 16 TO-220AB / c 2 D PAK T = 130 C Per diode 10 Average forward current c I A F(AV) = 0.5 T = 120 C Per device 20 c T = 110 C Per diode 8 c TO-220FPAB T = 80 C Per device 16 c I Surge non repetitive forward current t = 10 ms sinusoidal 120 A FSM p T Storage temperature range -65 to + 175 C stg T Maximum operating junction temperature 175 C j Table 3. Thermal resistance Symbol Parameter Maximum Unit 2 TO-220AB / D PAK Per diode 2.5 TO-220FPAB Per diode 5 C/ R Junction to case th(j-c) 2 W TO-220AB / D PAK Total 1.6 TO-220FPAB Total 3.8 2 TO-220AB / D PAK 0.7 C/ R Coupling th(c) W TO-220FPAB 2.5 When the diodes 1 and 2 are used simultaneously: T = P x R + P x R j (diode1) (diode1) th(j-c) (per diode) (diode2) th(c) Table 4. Static electrical characteristics Symbo Parameter Test conditions Min. Typ Max. Unit l T = 25 C 8 j (1) I Reverse leakage current V = V A R R RRM T = 150 C 25 240 j T = 25 C 1.8 j I = 8 A F T = 150 C 1.05 1.35 j (2) V Forward voltage drop V F T = 25 C 2.08 j I = 16 A F T = 150 C 1.28 1.64 j 1. Pulse test: t = 5 ms, < 2 % p 2. Pulse test: t = 380 s, < 2 % p To evaluate the maximum conduction losses use the following equation: 2 P = 1.06 x I + 0.036 I F(AV) F (RMS) 2/10 Doc ID 10760 Rev 2