STTH30RQ06 Datasheet 600 V, 30 A ultrafast high voltage rectifier Features K A High junction temperature capability K K Ultrafast with soft recovery behavior Low reverse current A A K A NC DPAK NC DPAK HV Low thermal resistance Reduce switching and conduction losses K K DPAK HV creepage distance (anode to cathode) = 5.38 mm min. (with top coating) A ECOPACK2 compliant (DO-247, TO-220AC, DO-247 LL) K A DO-247 K TO-220AC Applications K Output rectification PFC UPS A DO-247 LL Air conditioning K Charging station Description The STTH30RQ06 has been developed to be used in application requiring a high- voltage secondary rectification for LLC full bridge topology. Product status link It is also suited for use in switching power supplies, industrial applications, as rectification, freewheeling and clamping diode. STTH30RQ06 Product summary I 30 A F(AV) V 600 V RRM V (typ.) 1.45 V F t (max.) 30 ns rr T 175 C j DS12164 - Rev 5 - March 2020 www.st.com For further information contact your local STMicroelectronics sales office.STTH30RQ06 Characteristics 1 Characteristics Table 1. Absolute ratings (limiting values, at 25 C, unless otherwise specified) Symbol Parameter Value Unit V Repetitive peak reverse voltage 600 V RRM I Forward rms current 50 A F(RMS) I T = 103 C, = 0.5 square Average forward current 30 A F(AV) C DPAK, DPAK HV 180 I Surge non repetitive forward current t = 10 ms sinusoidal A FSM p TO-220AC, DO-247, DO-247 LL 200 -65 to T Storage temperature range C stg +175 T Maximum operating junction temperature 175 C j Table 2. Thermal parameters Max. Symbol Parameter Unit value R Junction to case 0.70 C/W th(j-c) R Junction to case DO-247 LL 0.90 C/W th(j-c) For more information, please refer to the following application note: AN5088: Rectifiers thermal management, handling and mounting recommendation Table 3. Static electrical characteristics Symbol Parameter Test conditions Min. Typ. Max. Unit T = 25 C - 40 j (1) I Reverse leakage current V = V A R RRM R T = 150 C - 80 800 j T = 25 C - 2.45 j I = 15 A F T = 150 C - 1.15 1.45 j (2) V Forward voltage drop V F T = 25 C - 2.95 j I = 30 A F T = 150 C - 1.45 1.85 j 1. Pulse test: t = 5 ms, < 2% p 2. Pulse test: t = 380 s, < 2% p To evaluate the conduction losses, use the following equation: 2 P = 1.05 x I + 0.026 x I F(AV) F (RMS) For more information, please refer to the following application notes related to the power losses: AN604: Calculation of conduction losses in a power rectifier AN4021: Calculation of reverse losses on a power diode AN5028: Calculation of turn-off power losses generated by an ultrafast diode DS12164 - Rev 5 page 2/20