STPS30120C Datasheet 120 V power Schottky rectifier A1 Features K A2 High junction temperature capability Avalanche rated Low leakage current K K Good trade-off between leakage current and forward voltage drop ECOPACK 2 compliant A2 A2 K K A1 A1 Applications TO-220AB TO-220AB narrow leads Switching diode SMPS DC/DC converter LED lighting Description Dual center tap Schottky rectifier suited for high frequency switch mode power supply. Packaged in TO-220AB and TO-220AB narrow leads, the STPS30120C is optimized for use in notebook adaptors, LCD adaptors and desktop SMPS, providing in these applications a margin between the remaining voltages applied on the diode and the voltage capability of the diode. Product status link STPS30120C Product summary Symbol Value I 2 x 15 A F(AV) V 120 V RRM T (max.) 175 C j V (typ.) 0.70 V F DS4230 - Rev 5 - June 2018 www.st.com For further information contact your local STMicroelectronics sales office.STPS30120C Characteristics 1 Characteristics Table 1. Absolute ratings (limiting values at 25 C, per diode, unless otherwise specified) Symbol Parameter Value Unit V Repetitive peak reverse voltage 120 V RRM I Forward rms current 30 A F(RMS) T = 145 C Per diode 15 c I Average forward current , = 0.5 A F(AV) T = 140 C Per device 30 c I Surge non repetitive forward current t = 10 ms sinusoidal 180 A FSM p P Repetitive peak avalanche power t = 10 s, T = 125 C 480 W ARM p j T Storage temperature range -65 to +175 C stg (1) T 175 C j Maximum operating junction temperature 1. (dP /dT ) < (1/R ) condition to avoid thermal runaway for a diode on its own heatsink. tot j th(j-a) Table 2. Thermal resistance parameters Symbol Parameter Max. value Unit Per diode 2.2 R Junction to case th(j-c) Total 1.3 C/W R Coupling 0.3 th(c) When the diodes 1 and 2 are used simultaneously: T (diode 1) = P(diode 1) x R (per diode) + P(diode 2) x R j th(j-c) th(c) Table 3. Static electrical characteristics (per diode) Symbol Parameter Test conditions Min. Typ. Max. Unit T = 25 C - 15 A j (1) I V = V Reverse leakage current R R RRM T = 125 C - 2.5 7.5 mA j T = 25 C - 0.74 j I = 5 A F T = 125 C - 0.57 0.61 j T = 25 C - 0.92 j (2) V Forward voltage drop I = 15 A V F F T = 125 C - 0.70 0.74 j T = 25 C - 1.02 j I = 30 A F T = 125 C - 0.83 0.89 j 1. Pulse test: t = 5 ms, < 2% p 2. Pulse test: t = 380 s, < 2% p To evaluate the conduction losses, use the following equation: 2 P = 0.59 x I + 0.01 x I F(AV) F (RMS) For more information, please refer to the following application notes related to the power losses : DS4230 - Rev 5 page 2/11