STPS5H100-Y Datasheet Automotive high voltage power Schottky rectifier Features A K AEC-Q101 qualified Negligible switching losses High junction temperature capability Low leakage current Good trade-off between leakage current and forward voltage drop Avalanche specification PPAP capable V guaranteed from -40 C to +175 C RRM Description The STPS5H100-Y is housed in a DPAK package. This high voltage Schottky barrier rectifier is designed for high frequency miniature switched mode power supplies and on board DC to DC converters for automotive applications. It is ideally suited for LED lighting and car radio applications, as well as ECU (Engine Control Unit) in automotive environment. Product status link STPS5H100-Y Product summary Symbol Value I 5 A F(AV) V 100 V RRM T range -40 C to +175 C j V (max.) 0.61 V F DS6906 - Rev 2 - April 2018 www.st.com For further information contact your local STMicroelectronics sales office.STPS5H100-Y Characteristics 1 Characteristics Table 1. Absolute ratings (limiting values at 25 C, unless otherwise specified) Symbol Parameter Value Unit V Repetitive peak reverse voltage, T = -40 C to +175 C 100 V RRM j I Forward rms current 10 A F(RMS) I Average forward current T = 165 C, = 0.5 5 A F(AV) c I Surge non repetitive forward current t = 10 ms sinusoidal 75 A FSM p P Repetitive peak avalanche power t = 10 s, T = 125 C 518 W ARM p j T Storage temperature range -65 to +175 C stg (1) T Operating junction temperature range -40 to +175 C j 1. (dP /dT ) < (1/R ) condition to avoid thermal runaway for a diode on its own heatsink. tot j th(j-a) Table 2. Thermal parameters Symbol Parameter Max. value Unit R Junction to case 2.5 C/W th(j-c) Table 3. Static electrical characteristics Symbol Parameter Test conditions Min. Typ. Max. Unit T = 25 C - 3.5 A j (1) I Reverse leakage current V = V R R RRM T = 125 C - 1.3 4.5 mA j T = 25 C - 0.73 j I = 5 A F T = 125 C - 0.57 0.61 j (2) V Forward voltage drop V F T = 25 C - 0.85 j I = 10 A F T = 125 C - 0.66 0.71 j 1. Pulse test: tp = 5 ms, < 2% 2. Pulse test: t = 380 s, < 2% p To evaluate the conduction losses, use the following equation: 2 P = 0.51 x I + 0.02 x I F(AV) F (RMS) DS6906 - Rev 2 page 2/9