STTH60L06TV Turbo 2 ultrafast high voltage rectifier Main product characteristics I 2 x 40 A F(AV) A1 K1 A1 K2 V 600 V RRM T 150 C j V (typ) 1.30 V F A2 K2 K1 A2 t (typ) 50 ns rr STTH60L06TV2 STTH60L06TV1 Features and benefits A1 A1 K1 K2 Ultrafast switching Low reverse current A2 K1 Low thermal resistance A2 K2 Reduces switching & conduction losses ISOTOP Insulated package: Electrical insulation = 2500 V RMS Capacitance = 45 pF Order codes Description Part Number Marking The STTH60L06TV, which is using ST Turbo 2 600V technology, is specially suited for use in STTH60L06TV1 STTH60L06TV1 switching power supplies, and industrial STTH60L06TV2 STTH60L06TV2 applications (such as welding), as rectification diode. Table 1. Absolute ratings (limiting values per diode at 25 C, unless otherwise specified) Symbol Parameter Value Unit V Repetitive peak reverse voltage 600 V RRM I RMS forward current 100 A F(RMS) T = 75 C per diode 30 A c I Average forward current, = 0.5 F(AV) T = 70 C per diode 40 c I Surge non repetitive forward current t = 10 ms Sinusoidal 210 A FSM p T Storage temperature range -55 to + 150 C stg T Maximum operating junction temperature 150 C j October 2006 Rev 3 1/7 www.st.comCharacteristics STTH60L06TV 1 Characteristics Table 2. Thermal parameters Symbol Parameter Value Unit Per diode 1.60 R Junction to case th(j-c) Total 0.85 C/W R Coupling thermal resistance 0.1 th(c) When the diodes are used simultaneously: T = P x R (per diode) + P x R j(diode1) (diode1) th(j-c) (diode2) th(c) Table 3. Static electrical characteristics (per diode) Symbol Parameter Test conditions Min. Typ Max. Unit T = 25 C 25 j (1) I Reverse leakage current V = V A R R RRM T = 125 C 25 250 j T = 25 C 1.55 j (2) V Forward voltage drop I = 60 A V F F T = 150 C 1.0 1.25 j 1. Pulse test: t = 5 ms, < 2 % p 2. Pulse test: t = 380 s, < 2 % p To evaluate the conduction losses use the following equation: 2 P = 0.95 x I + 0.010 I F(AV) F (RMS) Table 4. Dynamic characteristics (per diode) Test conditions Symbol Parameter Min. Typ Max. Unit I = 0.5 A, I = 0.25 A F rr 65 I = 1 A, T = 25 C R j t Reverse recovery time ns rr I = 1 A, dI /dt = 50 A/s, F F 65 90 V = 30 V, T = 25 C R j I = 30 A, dI /dt = 100 A/s, F F I Reverse recovery current 11.5 16 A RM V = 400 V, T = 125 C R j I = 30 A dI /dt = 100 A/s F F t Forward recovery time 500 ns fr V = 1.1 x V , T = 25 C FR Fmax j I = 30 A, dI /dt = 100 A/s, F F V Forward recovery voltage 2.5 V FP V = 1.1 x V , T = 25 C FR Fmax j 2/7