STPS640C-Y Automotive power Schottky rectifier Datasheet production data Description A1 K This dual Schottky rectifier is designed for switch A2 mode power supplies and other power converters. K This device is intended for use in low and medium voltage operation, and in particular high frequency circuits where low switching losses are required (free wheeling and polarity protection) in automotive applications. A2 Table 1. Device summary A1 Symbol Value DPAK I 2 x 3 A STPS640CBY-TR F(AV) V 40 V RRM Features T 150 C j V 0.50 V Low forward voltage drop F (Typ) Very small conduction losses Negligible switching losses Extremely fast switching Low thermal resistance AEC-Q101 qualified. December 2013 DocID025068 Rev 2 1/8 This is information on a product in full production. www.st.comCharacteristics STPS640C-Y 1 Characteristics Table 2. Absolute ratings (limiting values, per diode) Symbol Parameter Value Unit V Repetitive peak reverse voltage 40 V RRM I Forward rms current 6 A F(RMS) per diode 3 I Average forward current, = 0.5, T = 135 C A F(AV) c per device 6 I Surge non repetitive forward current t = 10 ms sinusoidal, T = 25 C 75 A FSM p c I Peak repetitive reverse current t = 2 s, F = 1kHz 1 A RRM p P Repetitive peak avalanche power t = 1 s, T = 25 C 1300 W ARM p c T Storage temperature range -65 to +150 C stg T Operating junction temperature -40 to +150 C j Table 3. Thermal parameters Symbol Parameter Value Unit per diode 5.5 R Junction to case th(j-c) per device 3 C/W R coupling 0.5 th(c) When the diodes 1 and 2 are used simultaneously : Tj(diode 1) = P(diode1) x R (Per diode) + P(diode 2) x R th(j-c) th(c) Table 4. Static electrical characteristics (per diode) Symbol Parameter Test conditions Min. Typ Max. Unit T = 25 C - - 100 A j (1) I Reverse leakage current V = V R R RRM T = 125 C - 2 10 mA j T = 25 C - - 0.63 j I = 3 A F T = 125 C - 0.50 0.57 j (2) V Forward voltage drop V F T = 25 C - - 0.84 j I = 6 A F T = 125 C - 0.67 0.72 j 1. Pulse test: t = 5 ms, < 2% p 2. Pulse test: t = 380 s, < 2% p To evaluate the conduction losses use the following equation: 2 P = 0.42 x I + 0.050 x I F(AV) F (RMS) 2/8 DocID025068 Rev 2