STPS8L30BY-TR STMicroelectronics

STPS8L30-Y Automotive low drop power Schottky rectifier Datasheet production data Features Low cost device with low drop forward voltage K for less power dissipation and reduced heatsink. Optimized conduction/reverse losses trade-off A which leads to the highest yield in the NC application. DPAK High power surface mount miniature package. STPS8L30BY-TR AEC-Q101 qualified. Description Table 1. Device summary Single Schottky rectifier is suited to switched Symbol Value mode power supplies and high frequency DC to DC converters. I 8 A F(AV) Packaged in DPAK, this device is especially V 30 V RRM intended for use as a rectifier at the SMPS or T 150 C j DC/DC units polarity protection in automotive V 0.40 V applications. F (MAX) July 2013 DocID024083 Rev 1 1/8 This is information on a product in full production. www.st.comCharacteristics STPS8L30-Y 1 Characteristics Table 2. Absolute ratings (limiting values) Symbol Parameter Value Unit V Repetitive peak reverse voltage 30 V RRM I Forward rms current 7 A F(RMS) I Average forward current, = 0.5 T = 135 C 8 A F(AV) c I Surge non repetitive forward current t = 10 ms sinusoidal 75 A FSM p I Peak repetitive reverse current t = 2 s, F = 1kHz square 1 A RRM p I Non repetitive peak reverse current t = 100 s square 2 A RSM p T Storage temperature range -65 to +150 C stg (1) T Operating junction temperature -40 to +150 C j dV/dt Critical rate of rise of reverse voltage 10000 V/s dPtot 1 1. condition to avoid thermal runaway for a diode on its own heatsink < Rth(j-a) dTj Table 3. Thermal parameters Symbol Parameter Value Unit R Junction to case 2.5 C/W th(j-c) Table 4. Static electrical characteristics (per diode) Symbol Parameter Test conditions Min. Typ Max. Unit T = 25 C -- 1 j (1) I Reverse leakage current V = V mA R R RRM T = 100 C - 15 40 j T = 25 C - - 0.49 j I = 8 A F T = 125 C - 0.35 0.40 j (2) V Forward voltage drop V F T = 25 C - - 0.63 j I = 16 A F T = 125 C - 0.448 0.57 j 1. Pulse test: t = 5 ms, < 2% p 2. Pulse test: t = 380 s, < 2% p To evaluate the conduction losses use the following equation: 2 P = 0.23 x I + 0.021 x I F(AV) F (RMS) 2/8 DocID024083 Rev 1